Description
Manufacturer | ABB |
Brand | ABB |
Series | module |
Part Number | TC512V1 3BSE018059R1 |
Product Type | module |
Quality | 100% New Original |
Stock | In stock |
Delivery time | 1-3 days after Payment |
After-sales Service | Have |
Warranty | 1 year |
Shipping term | DHL / FEDEX/ EMS /UPS/TNT/EMS |
Packaging details: if you need an urgent delivery order, please feel free to contact us, and we will do our best to meet your needs.
Price problem: if you find that other suppliers offer cheaper prices for the same product, we are also willing to provide you with reference prices and give you further discounts.
Example 1
To calculate a voltage drop on a three-phase cable with the following
specifications:
• rated voltage: 400 V;
• cable length: 25 m;
• cable formation: single-core copper cable, 3×50 mm2
;
• load current I
b: 100 A;
• power factor cosϕ: 0.9.
From Table 4, for a 50 mm2
single-core cable it is possible to read that a ∆Ux
voltage drop corresponds to 0.81 V/(A⋅km). By multiplying this value by the
length in km and by the current in A, it results:
which corresponds to this percentage value:
Example 2
To calculate a voltage drop on a three-phase cable with the following
specifications:
• rated voltage: 690 V;
• cable length: 50 m;
• cable formation: multi-core copper cable, 2x(3×10) mm2
;
• load current I
b: 50 A;
• power factor cosϕ: 0.85.
From Table 5, for a multi-core 10 mm2
cable it is possible to read that ∆Ux
voltage drop corresponds to 3.42 V/(A⋅km). By multiplying this value by the
length in km and by the current in A, and by dividing it by the number of cables
in parallel,
Method for defining the cross section of the conductor according to
voltage drop in the case of long cables
In the case of long cables, or if particular design specifications impose low
limits for maximum voltage drops, the verification using as reference the cross
section calculated on the basis of thermal considerations (calculation according
to chapter 1.2.1 “Current carrying capacity and methods of installation”) may
have a negative result.
To define the correct cross section, the maximum ∆Uxmax value calculated by
using the formula:
is compared with the corresponding values on Tables 4÷12 by choosing the
smallest cross section with a ∆Ux
value lower than ∆Uxmax.
Example:
Supply of a three-phase load with Pu
= 35 kW (Ur
=400 V, fr
= 50 Hz, cosϕ=0.9)
with a 140 m cable installed on a perforated tray, consisting of a multi-core
copper cable with EPR insulation.
Maximum permitted voltage drop 2%.
Load current I
b is:
The Table 8 of Chapter 1.2.1 shows S = 10 mm2
.
From Table 4, for the multi-core 10 mm2
cable it is possible to read that the
voltage drop per A and per km is 3.60 V/(A⋅km). By multiplying this value by
the length in km and by the current in A, it results:
which corresponds to this percentage value:
This value is too high.